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Question

In general, in an alternating current circuit

The correct answer is

the average value of current is zero

Understanding Alternating Current (AC) Circuits

In electrical circuits, we often deal with two types of current: Direct Current (DC) and Alternating Current (AC). DC flows in only one direction, while AC periodically reverses its direction.

A common form of alternating current is sinusoidal, represented by the equation:

\(I(t) = I_0 \sin(\omega t)\)

where:

  • \(I(t)\) is the instantaneous current at time \(t\).
  • \(I_0\) is the peak value of the current.
  • \(\omega\) is the angular frequency.

Average Value of Current in an AC Cycle

When we talk about the average value of alternating current, we usually consider the average over one complete cycle. A complete cycle includes both the positive and negative halves of the waveform. For a sinusoidal AC, the positive half-cycle has the same shape and area as the negative half-cycle.

Mathematically, the average value of the current \(I_{\text{avg}}\) over one time period \(T\) is given by:

\(I_{\text{avg}} = \frac{1}{T} \int_0^T I(t) dt\)

For \(I(t) = I_0 \sin(\omega t)\) and \(T = \frac{2\pi}{\omega}\):

\(I_{\text{avg}} = \frac{1}{T} \int_0^T I_0 \sin(\omega t) dt = \frac{I_0}{T} \left[-\frac{\cos(\omega t)}{\omega}\right]_0^T\)

\(I_{\text{avg}} = \frac{I_0}{\omega T} [-\cos(\omega T) - (-\cos(0))] = \frac{I_0}{2\pi} [-\cos(2\pi) + \cos(0)]\)

\(I_{\text{avg}} = \frac{I_0}{2\pi} [-1 + 1] = 0\)

Thus, the average value of current over a complete cycle in an alternating current circuit is generally zero.

Analyzing the Options

Let's look at the given options in the context of a general alternating current circuit:

  1. the average value of current is zero: As shown above, for standard AC waveforms like sinusoidal, the average current over a full cycle is indeed zero. This is a general property.
  2. the average value of square of the current is zero: The square of the current, \(I^2(t) = I_0^2 \sin^2(\omega t)\), is always non-negative. The average value of the square of the current is related to the Mean Square (MS) value, which leads to the Root Mean Square (RMS) value. The average value of \(I^2\) over a cycle is \(\frac{I_0^2}{2}\) for a sinusoidal AC. This is not zero unless \(I_0=0\).
  3. average value of power dissipation is zero: The instantaneous power dissipated in a circuit element is \(P(t) = V(t) I(t)\). The average power dissipated over a cycle is \(P_{\text{avg}} = V_{\text{rms}} I_{\text{rms}} \cos(\phi)\), where \(\phi\) is the phase difference between voltage and current. This average power is zero only in purely inductive or purely capacitive circuits (where \(\phi = \pm \frac{\pi}{2}\) and \(\cos(\phi) = 0\)). In circuits with resistance, the average power dissipation is not zero. Therefore, this is not true in general for any AC circuit.
  4. the phase difference between voltage and current is zero: The phase difference (\(\phi\)) between voltage and current in an AC circuit depends on the components present. It is zero only in a purely resistive circuit. In circuits containing inductors or capacitors, the phase difference is non-zero (\(\phi = \frac{\pi}{2}\) for a pure inductor, \(\phi = -\frac{\pi}{2}\) for a pure capacitor). Therefore, this is not true in general for any AC circuit.

Conclusion

Based on the analysis, the only statement that is generally true for an alternating current circuit (when considering averages over a full cycle for typical AC waveforms) is that the average value of the current is zero.

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