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Question

If $2 \text{ \# } 3 = 13$, $3 \text{ \# } 4 = 25$, then $4 \text{ \# } 5 = ?$

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
41

Identify the $a \text{ \# } b$ Pattern Rule

The question presents a custom mathematical operation '#'. We need to find the rule that defines this operation using the provided examples.

Analyzing Examples

We are given:

  • $2 \text{ \# } 3 = 13$
  • $3 \text{ \# } 4 = 25$

Let's test the hypothesis that the operation follows the rule $a \text{ \# } b = a^2 + b^2$.

  • For the first case ($a=2, b=3$): $2^2 + 3^2 = 4 + 9 = 13$. This matches.
  • For the second case ($a=3, b=4$): $3^2 + 4^2 = 9 + 16 = 25$. This also matches.

The pattern $a \text{ \# } b = a^2 + b^2$ is confirmed.

Calculate $4 \text{ \# } 5$

Using the confirmed pattern $a \text{ \# } b = a^2 + b^2$, we can now calculate $4 \text{ \# } 5$.

Here, $a=4$ and $b=5$.

$ 4 \text{ \# } 5 = 4^2 + 5^2 $

Calculate the terms:

  • $4^2 = 16$
  • $5^2 = 25$

Add the results:

$ 16 + 25 = 41 $

Thus, $4 \text{ \# } 5 = 41$.

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