Number Transformation and Digit Product

This solution details the process of modifying a number based on its odd digits and calculating the product related to the repeated digits in the new number.

Step 1: Modify Odd Digits

The original number is 95423671.

The odd digits in this number are 9, 5, 7, and 1.

Subtract 1 from each of these odd digits:

• $9 - 1 = 8$
• $5 - 1 = 4$
• $7 - 1 = 6$
• $1 - 1 = 0$

Step 2: Construct the New Number

Replace the odd digits in the original number with their newly calculated values. The even digits remain unchanged.

• The digit 9 is replaced by 8.
• The digit 5 is replaced by 4.
• The digit 7 is replaced by 6.
• The digit 1 is replaced by 0.
• The even digits 4, 2, 3, 6 stay the same.

The sequence of digits transforms from 9, 5, 4, 2, 3, 6, 7, 1 to 8, 4, 4, 2, 3, 6, 6, 0.

The new number formed is 84423660.

Step 3: Identify Repeated Digits and Calculate Product

Examine the digits present in the new number: {8, 4, 4, 2, 3, 6, 6, 0}.

Identify the digits that appear more than once in this sequence. These are 4 (appears twice) and 6 (appears twice).

To find the required product, we use the highest digit present in the new number and the highest digit among those that are repeated.

• The highest digit in the number 84423660 is 8.
• The digits repeated more than once are 4 and 6. The highest among these is 6.

The product is calculated as:

Product = (Highest digit in new number) $\times$ (Highest repeated digit)

Calculation: $8 \times 6 = 48$.