To find the numbers between 1 and 100 that are divisible by both 6 and 8, we need to find numbers divisible by their Least Common Multiple (LCM).
First, find the prime factorization of each number:
The LCM is found by taking the highest power of each prime factor present:
LCM(6, 8) = $2^3 \times 3 = 8 \times 3 = 24$
We need to count the multiples of 24 that fall within the range of 1 to 100.
List the multiples of 24:
The next multiple, $24 \times 5 = 120$, is greater than 100 and thus outside the specified range.
The numbers between 1 and 100 divisible by both 6 and 8 are 24, 48, 72, and 96.
There are 4 such numbers.
Find the least value of x for which 57x716 is divisible by 9.
Which of the following numbers is NOT divisible by 11?
If 321y72 is a multiple of 6, where y is a digit, what is the least value of y?
From the given numbers A, B, C and D, which number is NOT divisible by 11?
A = 712712
B = 177210
C = 64614
D = 756148
Which of the following numbers is divisible by 7 ?