We need to find the largest 4-digit number that can be divided evenly by 66.
A number is divisible by 66 if it is divisible by both 2 and 33. Since $66 = 6 \times 11$, and 6 and 11 are coprime, the number must be divisible by both 6 and 11. This means it must be divisible by 2, 3, and 11.
$ \frac{9999}{66} $
Performing the division gives us a quotient and a remainder:
$ 9999 = 66 \times 151 + 33 $
The quotient is 151, and the remainder is 33.
$ \text{Result} = 9999 - \text{Remainder} $
$ = 9999 - 33 $
$ = 9966 $
Therefore, the largest 4-digit number completely divisible by 66 is 9966.
If the number 6484a6 is divisible by 8, then find the least value of a.