The expression given is $4^7 - 4$. We first factorize it:
$4^7 - 4 = 4 \times (4^6 - 1)$
Since $4^7 - 4 = 4(4^6 - 1)$, the expression is a multiple of 4. Any multiple of 4 is also a multiple of 2. Thus, $4^7 - 4$ is divisible by 2.
From the factorization $4(4^6 - 1)$, it is evident that the expression contains a factor of 4. Thus, $4^7 - 4$ is divisible by 4.
To check divisibility by 7, we evaluate the expression modulo 7:
$4^3 \equiv 1 \pmod{7}$
$4^7 = 4^{3 \times 2 + 1} = (4^3)^2 \times 4^1 \equiv 1^2 \times 4 \equiv 4 \pmod{7}$
Therefore, $4^7 - 4 \equiv 4 - 4 \equiv 0 \pmod{7}$.
This confirms that $4^7 - 4$ is divisible by 7.
Consider the factored form $4(4^6 - 1)$.
$4^6 = (2^2)^6 = 2^{12}$.
The expression is $4(2^{12} - 1)$.
$2^{12} - 1$ is an odd number.
Let $2^{12} - 1 = k$, where $k$ is odd. The expression is $4k$.
A number of the form $4 \times \text{odd}$ is never divisible by 8. For $4k$ to be divisible by 8, $k$ would need to be even ($4k = 8m \implies k=2m$), which contradicts $k$ being odd.
Thus, $4^7 - 4$ is NOT a multiple of 8.
The expression $4^7 - 4$ is confirmed to be a multiple of 2, 4, and 7. However, it is not a multiple of 8.
Therefore, 8 is the number that is NOT a multiple of $4^7 - 4$.
If the number 6484a6 is divisible by 8, then find the least value of a.