Four numbers a, b, c and d satisfy the relation (a + 2) : (b − 2) = (c + 4) : (d − 4). If a = 6, b = 8 and c = 12, find the value of d.
16
The given proportion is \((a+2):(b-2)=(c+4):(d-4)\).
Substituting \(a=6\) and \(b=8\), the left ratio is \((6+2):(8-2)=8:6=4:3\).
Substituting \(c=12\), the right ratio is \((12+4):(d-4)=16:(d-4)\).
Equating: \(\frac{4}{3}=\frac{16}{d-4}\), so \(4(d-4)=48\), giving \(d-4=12\) and \(d=16\).
Hence, the value of d is 16.
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