coins in all denominations. What is the total number of coins in the box?
The problem requires finding the total number of coins given the total amount and the denominations (Rs. 1, Rs. 5, Rs. 10), with the condition that the count of each coin type is equal.
Let '$x$' represent the number of coins for each denomination. Since there are equal numbers of Rs. 1, Rs. 5, and Rs. 10 coins, the value contributed by one coin of each denomination is:
The combined value of one set (one coin of each denomination) is the sum of their individual values:
Value per set = $x + 5x + 10x = 16x$ rupees
The total amount in the box is Rs. 4320. Since each set of coins (one of each denomination) is worth Rs. 16x, we can find the value of '$x$' by dividing the total amount by the value per set:
Total Amount = Number of sets $\times$ Value per set
Rs. 4320 = $x \times 16x$ (This interpretation seems wrong based on the problem statement - 'x' is the number of *each* coin, not the number of sets. Let's correct the approach.)
Let '$x$' be the number of coins of *each* denomination (Rs. 1, Rs. 5, Rs. 10).
The total value is given by:
$ (1 \times x) + (5 \times x) + (10 \times x) = 4320 $Combine the terms:
$ 1x + 5x + 10x = 4320 $ $ 16x = 4320 $Solve for '$x$':
$ x = \frac{4320}{16} $ $ x = 270 $This means there are 270 coins of each denomination (270 one rupee coins, 270 five rupee coins, and 270 ten rupee coins).
The total number of coins is the sum of the counts for each denomination:
Total Coins = (Number of Rs. 1 coins) + (Number of Rs. 5 coins) + (Number of Rs. 10 coins)
Total Coins = $x + x + x = 3x$
Substitute the value of '$x$':
Total Coins = $3 \times 270$
Total Coins = 810