Find the value of (1.19̄)^2 + 2 × 1.19̄ × 1.79̄ + (1.79̄)^2:
9
The expression is a perfect square: (1.19̄ + 1.79̄)^2. Since 1.1\overline{9} = 1.2 and 1.7\overline{9} = 1.8 (repeating 9 rounds up), the sum is 1.2 + 1.8 = 3, and 3^2 = 9.
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