The question asks us to identify which of the given numbers (3, 15, 5, 14) divides the number 386937355 without leaving a remainder. We can determine this by applying the divisibility rules for each number.
Let's review the rules we'll use:
First, we sum the digits of 386937355:
Sum = $3 + 8 + 6 + 9 + 3 + 7 + 3 + 5 + 5 = 49$.
Now, we check if the sum (49) is divisible by 3.
$49 \div 3 = 16$ with a remainder of 1.
Since the sum of the digits is not divisible by 3, the number 386937355 is not divisible by 3.
We look at the last digit of 386937355.
The last digit is 5.
According to the rule, if the last digit is 0 or 5, the number is divisible by 5. Therefore, 386937355 is divisible by 5.
For a number to be divisible by 14, it must be divisible by both 2 and 7.
Check for Divisibility by 2: A number is divisible by 2 if its last digit is even (0, 2, 4, 6, 8). The last digit of 386937355 is 5, which is odd. So, 386937355 is not divisible by 2.
Since 386937355 is not divisible by 2, it cannot be divisible by 14, regardless of whether it's divisible by 7.
For a number to be divisible by 15, it must be divisible by both 3 and 5.
From our previous checks:
Since it fails the divisibility test for 3, the number 386937355 is not divisible by 15.
By applying the standard divisibility rules, we found the following:
Therefore, the only number among the choices provided that divides 386937355 is 5.
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 8317456, what will be the sum of the digits that are second from the left and second from the right?
This question is based on the five, three-digit numbers given below.
(Left) 126 257 352 984 751 (Right)
(Example- 697 - First digit = 6, second digit = 9 and third digit = 7)
(NOTE: All operations to be done from left to right.)
If 2 is added in the third digit of each number, how many numbers thus formed will be odd numbers?