This question is based on the five, three-digit numbers given below. (Left) 126 257 352 984 751 (Right) If 2 is added in the third digit of each number, how many numbers thus formed will be odd numbers?
(Example- 697 - First digit = 6, second digit = 9 and third digit = 7)
(NOTE: All operations to be done from left to right.)
Two
To determine how many numbers will be odd after adding 2 to the third digit (the ones place) of each number, we can follow these steps:
A number is odd if its units (third) digit is 1, 3, 5, 7, or 9.
A number is even if its units (third) digit is 0, 2, 4, 6, or 8.
Adding 2 to the units digit of any number does not change its parity.
An even number + 2 = Even number.
An odd number + 2 = Odd number.
Let's look at the given set: 126, 257, 352, 984, 751
| Original Number | Third Digit | New Third Digit (+2) | New Number | Parity |
|---|---|---|---|---|
| 126 | 6 | 8 | 128 | Even |
| 257 | 7 | 9 | 259 | Odd |
| 352 | 2 | 4 | 354 | Even |
| 984 | 4 | 6 | 986 | Even |
| 751 | 1 | 3 | 753 | Odd |
The numbers that remain/become odd are 259 and 753.
There are Two such numbers.
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 8317456, what will be the sum of the digits that are second from the left and second from the right?