If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 8317456, what will be the sum of the digits that are second from the left and second from the right?
The problem asks us to modify a given number, 8317456, based on specific rules for its digits. We need to add 1 to every odd digit and subtract 2 from every even digit. After modifying the digits, we need to find the sum of two specific digits: the one that is second from the left and the one that is second from the right in the modified number.
Let's break down the original number 8317456 digit by digit and apply the given rules:
| Original Digit | Parity | Operation | Calculation | Modified Digit |
|---|---|---|---|---|
| 8 | Even | Subtract 2 | $8 - 2$ | 6 |
| 3 | Odd | Add 1 | $3 + 1$ | 4 |
| 1 | Odd | Add 1 | $1 + 1$ | 2 |
| 7 | Odd | Add 1 | $7 + 1$ | 8 |
| 4 | Even | Subtract 2 | $4 - 2$ | 2 |
| 5 | Odd | Add 1 | $5 + 1$ | 6 |
| 6 | Even | Subtract 2 | $6 - 2$ | 4 |
After applying the operations, the sequence of modified digits forms the new number. Combining the results from the table above, the modified number is 6428264.
Now, we need to find the digits that are second from the left and second from the right in the modified number 6428264.
The final step is to sum the two identified digits:
Therefore, the sum of the digits that are second from the left and second from the right in the modified number is 10.
This question is based on the five, three-digit numbers given below.
(Left) 126 257 352 984 751 (Right)
(Example- 697 - First digit = 6, second digit = 9 and third digit = 7)
(NOTE: All operations to be done from left to right.)
If 2 is added in the third digit of each number, how many numbers thus formed will be odd numbers?