The question asks us to find the larger of two consecutive natural numbers whose product equals 6.
Let's represent the two consecutive natural numbers using algebra. If we call the smaller number '$n$', then the next consecutive number will be '$n+1$' (since they are natural numbers).
We are given that their product is 6. So, we can write the equation:
$n \times (n+1) = 6$
The question specifies that the numbers must be natural numbers. Natural numbers are positive integers (1, 2, 3,...).
We found that the smaller number, '$n$', is 2.
The two consecutive natural numbers are 2 and 3.
Let's check if their product is indeed 6:
$2 \times 3 = 6$
The condition is satisfied.
The two numbers are 2 and 3. Comparing them, the greater number is 3.
You can also solve this problem by testing the given options:
| Option Value (Greater Number) | Smaller Consecutive Number | Product | Matches Condition (Product = 6)? |
|---|---|---|---|
| 2 | 1 | $1 \times 2 = 2$ | No |
| 3 | 2 | $2 \times 3 = 6$ | Yes |
| 5 | 4 | $4 \times 5 = 20$ | No |
| 19 | 18 | $18 \times 19 = 342$ | No |
By testing the options, we see that when the greater number is 3, the smaller consecutive number is 2, and their product is 6. Therefore, 3 is the correct answer.
The two consecutive natural numbers are 2 and 3. The greater of these two numbers is 3.
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 8317456, what will be the sum of the digits that are second from the left and second from the right?
This question is based on the five, three-digit numbers given below.
(Left) 126 257 352 984 751 (Right)
(Example- 697 - First digit = 6, second digit = 9 and third digit = 7)
(NOTE: All operations to be done from left to right.)
If 2 is added in the third digit of each number, how many numbers thus formed will be odd numbers?