What is the smallest natural number which, when divided by 7, 9 and 11, leaves remainders 1, 3 and 5 respectively?
687
Note that in each case, divisor minus remainder is the same: 7-1=6, 9-3=6, 11-5=6. So the required number = LCM(7,9,11) - 6. Since 7, 9, 11 are pairwise coprime, LCM = 7×9×11 = 693. Required number = 693 - 6 = 687. Hence option (D) is correct.
Similar Questions
Satyam studies $\frac{2}{3}$ hour in the morning and $\frac{3}{4}$ hour in the evening every day. Then what is his total study time every day?
A number becomes 135 after a 50% increase. What is 20% of that original number?
0.8 of which number is equal to 0.00004?
Multiplicative inverse of '2' is how much more or less than the multiplicative inverse of 3?
Find the value of (1.19̄)^2 + 2 × 1.19̄ × 1.79̄ + (1.79̄)^2:
What is the value of $\sqrt{0.000169}$ + $\sqrt{0.0004}$
How many integers greater than 14 and less than 99 are of the form $2n^2+3$ (n$\epsilon$ N)?
Important Questions from Number System
What is the value of 1 2 + 2 2 + 3 2 + ......21 2 ?
Which sequence is correct to represent the hierarchical chain of number system?
(Where N - Natural Numbers
W - Whole Numbers
Q - Rational Numbers
Z - Integers)
What must be added to 45680 to make it exactly divisible by 9?
How many zeroes are there at the end of the following product?
1 x 5 x 10 x 15 x 20 x 25 x 30 x 35 x 40 x 45 x 50 x 55 x 60
Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by
