Find the sum of the mean, median and mode of the given data: 10, 8, 18, 12, 12, 12
36
36 is correct.
Mean = \(\dfrac{10 + 8 + 18 + 12 + 12 + 12}{6} = \dfrac{72}{6} = 12\).
Arranged in order: 8, 10, 12, 12, 12, 18. With 6 values, median = average of the 3rd and 4th values = \(\dfrac{12 + 12}{2} = 12\).
Mode = 12, since it occurs three times, more than any other value.
Sum = \(12 + 12 + 12 = 36\).
| Height (cm) | Number of persons |
|---|---|
| 120 | 3 |
| 130 | 4 |
| 140 | 5 |
| 150 | 6 |
| 160 | 2 |
| Value | 3 | 2 | k | 4 | 5 |
| Frequency | k | 2k | 3k | 4k | 5k |
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