The question asks for the remainder when the expression $7^6 + 5$ is divided by 6. We can solve this using modular arithmetic.
We need to find the value of $7^6 + 5 \pmod{6}$.
First, consider the base, 7, in modulo 6.
Since $7 = 1 \times 6 + 1$, we have $7 \equiv 1 \pmod{6}$.
Next, apply this to the term $7^6$. Using the property of modular arithmetic that if $a \equiv b \pmod{m}$, then $a^n \equiv b^n \pmod{m}$, we get:
$7^6 \equiv 1^6 \pmod{6}$
$7^6 \equiv 1 \pmod{6}$
Now, substitute this result back into the original expression:
$7^6 + 5 \pmod{6}$
Substitute $7^6 \equiv 1 \pmod{6}$: $1 + 5 \pmod{6}$
Calculate the final sum:
$1 + 5 = 6$
Since $6 = 1 \times 6 + 0$, we have $6 \equiv 0 \pmod{6}$.
Therefore, the remainder when $7^6 + 5$ is divided by 6 is 0.
The remainder in the expression $27\frac{3}{4}$ is:
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