The problem requires finding the maximum number of 17 cm pieces that can be cut from a 960 cm long rod. This is determined by dividing the total rod length by the length of each piece and taking the integer part of the result.
To find the maximum number of pieces, perform the division:
Number of pieces = Total length / Length per piece
Number of pieces = $\frac{960 \text{ cm}}{17 \text{ cm}}$
Performing the division:
$ \frac{960}{17} \approx 56.47 $Since only whole pieces can be cut, we take the integer part of the quotient, which is 56.
To confirm, calculate the length used for 56 pieces:
$ 56 \times 17 \text{ cm} = 952 \text{ cm} $The remaining length of the rod is:
$ 960 \text{ cm} - 952 \text{ cm} = 8 \text{ cm} $The remaining 8 cm is shorter than the required 17 cm length, so no additional pieces can be cut.
Therefore, the maximum number of 17 cm pieces that can be cut from a 960 cm rod is 56.
The remainder in the expression $27\frac{3}{4}$ is:
If a five digit number 247xy is divisible by 3, 7 and 11, then what is the value of (2y - 8x)?
If the seven-digit number 94x29y6 is divisible by 72, then what is the value of (2x + 3y) for x ≠ y ?
Find the greatest value of b so that 30a68b (a > b) is divisible by 11.
What is the remainder when the product of 335, 608 and 853 is divided by 13?