This solution explains how to find the remainder when the square of a number is divided by 7, given the remainder of the original number.
We are given a number that leaves a remainder of 4 when divided by 7. We need to find the remainder when the square of this number is divided by 7.
Start with the given congruence:
$N \equiv 4 \pmod{7}$
Square both sides of the congruence:
$N^2 \equiv 4^2 \pmod{7}$
Calculate the square of 4:
$N^2 \equiv 16 \pmod{7}$
Find the remainder when 16 is divided by 7:
16 can be written as $2 \times 7 + 2$.
Therefore, $16 \equiv 2 \pmod{7}$.
Substitute this back into the congruence for $N^2$:
$N^2 \equiv 2 \pmod{7}$
The remainder when the square of the number is divided by 7 is 2.
The remainder in the expression $27\frac{3}{4}$ is:
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