Hemisphere Curved Surface Area Calculation
The question asks for the curved surface area of a hemisphere with a given radius.
Formula and Given Values
The formula for the curved surface area (CSA) of a hemisphere is:
\( \text{CSA} = 2 \pi r^2 \)
Given the radius (\(r\)):
\( r = 125 \text{ cm} \)
Step-by-Step Calculation
Substitute the value of the radius into the formula:
\( \text{CSA} = 2 \pi (125)^2 \)
First, calculate the square of the radius:
\( 125^2 = 15625 \)
Now, multiply this by \(2\pi\):
\( \text{CSA} = 2 \pi \times 15625 \)
\( \text{CSA} = 31250 \pi \)
Final Answer
The curved surface area of the hemisphere is \(31250 \pi \text{ cm}^2\). This matches Option A.
Similar Questions
A steel plate is 20 mm thick and 45 mm wide. What is the length of the diagonal across the plate?
In a workshop calculation, you need to find the side of a square base with an area of 64 cm2. What is the correct length?
Calculate the area of an irregular plot using the Trapezoidal Rule, given the offsets are 2 m, 4 m, 3 m, and 5 m at an equal spacing of 1 m.
Find the circumference of a circle having radius 7 cm. Use π=22/7.
- The volume of a solid cylinder is 5,236 cm$^3$ and its height is 34 cm. What is the total surface area of the solid cylinder? $\left(\text{Use } \pi = \frac{22}{7}\right)$
In figure 'o' is the centre of a circle. The area of sector OAPB is $\frac{5}{18}$ of the area of the circle find $x$.
Important Questions from Mensuration
In a circular garden of radius 15 m, a path of 2 m wide has to be made inside the garden at the rate of ₹ 24 per sq. m. The cost of making the path is: (Take π = \(\frac{22}{7}\) )
A hollow cylinder with outer radius 4 cm and height 2 cm is made up of 1 cm thick metal sheet. What is the volume of metal used? (Take π = \(\frac{22}{7}\))
The sides of a triangular park are 60 m, 297 m and 303 m. Its area is equal to the area of a square-shaped garden. What is the perimeter (in m) of the garden?
The length and breadth of a rectangular field are in the ratio 4 : 3. If the cost of cultivating the field at ₹2 per m 2is ₹600, then the length of the field is:
A cylindrical tank has a capacity of 5632 m3. If the diameter of its base is 8 m, what is the depth of the cylindrical tank? (Use π = \(\frac{22}{7}\))
