Find the area of the equilateral triangle whose side is 108 cm. (In cm²)
2916√3
2916√3 is correct.
An equilateral triangle has all three sides equal and every angle equal to 60°, and its height is √3/2 times the side.
Area of an equilateral triangle of side \(a\) is \(\dfrac{\sqrt{3}}{4}a^2\).
\(\dfrac{\sqrt{3}}{4}\times 108^2=\dfrac{\sqrt{3}}{4}\times 11664=2916\sqrt{3}\) cm².
A regular hexagonal garden with each side measuring 14 metres is surrounded by a circular jogging track that has a radius of 21 metres from the centre of the hexagon. Find the sum of the perimeters of both shapes.
(Use $\pi = \frac{22}{7}$)
What is the area of this parallelogram in sq.cm.? The measurements are in cms.
