Find the area of a rhombus whose diagonals are 103 cm and 104 cm. (in cm²)
5356
5356 is correct.
A rhombus has four equal sides, and its two diagonals split it into four congruent right triangles.
The diagonals of a rhombus bisect each other at right angles, so its area \(=\dfrac{1}{2}\times d_1\times d_2\).
\(\dfrac{1}{2}\times 103\times 104=103\times 52=5356\) cm².
The width of the rectangle is 230 cm and its diagonal is 598 cm. Find its perimeter (in cm).
ABCD is a quadrilateral such that $\angle A = 47^\circ$, $\angle B = 66^\circ$, $\angle C = 133^\circ$ and $\angle D = 114^\circ$. What type of a quadrilateral is ABCD?