The width of the rectangle is 230 cm and its diagonal is 598 cm. Find its perimeter (in cm).
1564
1564 is correct.
In a rectangle the diagonal is the hypotenuse of the right triangle formed by the length and the width, so \(l=\sqrt{d^2-b^2}\).
\(l=\sqrt{598^2-230^2}=\sqrt{357604-52900}=\sqrt{304704}=552\) cm.
Perimeter \(=2(l+b)=2(552+230)=2\times 782=1564\) cm.
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