Find the area of a trapezium whose parallel sides are 8.4 cm and 10.8 cm respectively, and the distance between the parallel sides is 7.5 cm.
72 cm²
We are given a trapezium with parallel sides 8.4 cm and 10.8 cm, and the perpendicular distance (height) between them equal to 7.5 cm.
The area of a trapezium is found using the standard formula \(\text{Area}=\tfrac{1}{2}\times(\text{sum of parallel sides})\times \text{height}\).
Substituting the given values: \(\text{Area}=\tfrac{1}{2}\times(8.4+10.8)\times 7.5\)
First add the two parallel sides: \(8.4+10.8=19.2\) cm.
Now multiply by the height: \(19.2\times 7.5=144\).
Finally take half of this product: \(\tfrac{1}{2}\times 144=72\) cm².
Hence the area of the trapezium is 72 cm².
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