Find the number of unlike terms in (x + 2y + 3z)(2x - y + z).
6
Multiplying out \((x + 2y + 3z)(2x - y + z)\) term by term:
\(x(2x - y + z) = 2x^2 - xy + xz\)
\(2y(2x - y + z) = 4xy - 2y^2 + 2yz\)
\(3z(2x - y + z) = 6xz - 3yz + 3z^2\)
Adding and combining like terms: \(2x^2 - 2y^2 + 3z^2 + 3xy + 7xz - yz\).
This simplified expression has 6 unlike terms.
Similar Questions
Find degree of polynomial part when (2x³ + 3x² - x + 5) is divided by x.
Important Questions from Polynomials
If (x + y) 3+ 8 (x - y) 3= (3x + Ay) (3x 2+ Bxy + Cy 2), then the value of A + B + C is:
Given that x 8- 34x 4+ 1 = 0, x > 0. What is the value of (x 3+ x -3 )?
If \(x - \frac 3 x = 6,\; x \ne 0,\) then the value of \(\frac {x^4 - \frac {27}{x^2}}{x^2 - 3x - 3}\) is:
If \(x\left(3 - \frac 2 x\right) = \frac 3 x,\) then the value of \(x^3 - \frac 1 {x^3}\) is equal to:
The coefficient of x in (x – 3y) 3is:
