To find the magnification of the object placed in front of a convex mirror, we can use the formula for magnification \( m \) in the context of mirrors:
\(m = \frac{h'}{h} = \frac{-v}{u}\)
where:
For a convex mirror, the focal length \( f \) is positive. Given: \( f = 15 \, \text{cm} \) and \( u = -10 \, \text{cm} \).
Using the mirror formula,
\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)
Substitute the values:
\(\frac{1}{15} = \frac{1}{v} + \frac{1}{-10}\)
Rearrange to solve for \( \frac{1}{v} \):
\(\frac{1}{v} = \frac{1}{15} + \frac{1}{10}\)
Calculate the right-hand side:
\(\frac{1}{v} = \frac{2}{30} + \frac{3}{30} = \frac{5}{30} = \frac{1}{6}\)
Therefore,
\(v = 6 \, \text{cm}\)
Now calculate the magnification \( m \):
\(m = \frac{-v}{u} = \frac{-6}{-10} = +0.6\)
Hence, the magnification of the object by the convex mirror is +0.6.
Let's validate the options given in the question:
Which one of the following telescopes contains only mirrors?
The correct relation between the radius of curvature R and focal length f of a spherical mirror is
Spherical mirror formula relating an object distance ‘u’, image distance ‘v’ and focal length of mirror ‘f’ may be applied to a plane mirror when
The image of an object formed by a plane mirror is
The image we see in plane mirror is