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Question

An important figure of merit for microwave application of Schottky diode is forward bias cut off frequency fco and is given by :

This question was previously asked in
UGC NET 2023 Electronic Science Question Paper (13-Dec-2023) (Shift 1)
The correct answer is

\(\dfrac{1}{2\pi R_{F}C_{F}}\)

The cut-off frequency of a Schottky diode is the ordinary RC corner formed by its forward resistance and its junction capacitance :

\(f_{co}=\dfrac{1}{2\pi R_{F}C_{F}}\)

— option 3.

A dimensional check settles it without any physics. A frequency must have units of s−1. Since \(RC\) has units of seconds, \(1/2\pi RC\) is a frequency — but \(R^{2}C^{2}\) has units of s2, so options 1 and 2 would give s−2, and option 4's \(R^{2}C\) gives yet another wrong combination. Only option 3 is dimensionally a frequency at all.

What the two elements are. \(R_{F}\) is the diode's forward series resistance — the sum of the barrier's dynamic resistance and the ohmic resistance of the epitaxial layer and contacts. \(C_{F}\) is the junction capacitance of the metal-semiconductor barrier, which sits in parallel with it. The parallel capacitance shunts the signal, and above \(f_{co}\) it dominates, so the diode stops behaving as the non-linear element a mixer or detector needs.

Why this figure of merit matters for Schottky diodes in particular. A Schottky barrier is a majority-carrier device: conduction is by electrons flowing over the barrier, with essentially no minority-carrier injection and therefore no stored charge to be removed. That removes the reverse-recovery delay that limits p-n junction diodes, so the only remaining limit is the RC product — and it can be pushed very high:

\(R_{F}\approx5\ \Omega,\qquad C_{F}\approx0.1\ \text{pF}\quad\Rightarrow\quad f_{co}\approx320\ \text{GHz}\)

How the design is optimised. Both quantities are reduced by shrinking the anode: a smaller contact area lowers \(C_{F}\) directly, though it raises \(R_{F}\), so there is an optimum diameter for a given frequency — typically a few micrometres for millimetre-wave mixer diodes. This is exactly why the Schottky diode, and not the PIN or ordinary junction diode, is the standard microwave mixer and detector element.

Hence, fco = 1/(2πRFCF).

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Similar Questions

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    Which is correct ?

  2. ________ diode is not used as a microwave mixer or detector.

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Important Questions from Types of Diode

  1. A PIN diode can not be used as

    i. Microwave switch
    ii. Microwave mixer
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    Which is correct ?

  2. ________ diode is not used as a microwave mixer or detector.

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    List – I (Name of the Device)List – II (Application) 
    a. Diode i. Rectification
    b. Tunnel diodeii. Microwave switching
    c. Zener diodeiii. An oscillator
    d. PIN diodeiv. Voltage regulation

    Codes :

  4. Varacter diodes have the following properties :

    A. Junction capacitance varies with bias voltage

    B. Junction capacitance varies with time

    C. Non linearity of varacter diodes makes them suitable for frequency multipliers

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