An ice cream cone has a radius of 2 cm and slant height of 5 cm. If 100 such cones are to be painted externally (excluding base), what is the total painted area?
3140 cm2
Painting a cone “externally, excluding the base” means only the slanting curved surface of the cone gets paint; the flat circular base is left out.
The curved (lateral) surface area of a cone is \(\text{CSA} = \pi r l\), where \(r\) is the base radius and \(l\) is the slant height.
Here \(r = 2\ \text{cm}\) and \(l = 5\ \text{cm}\), and we take \(\pi = 3.14\).
CSA of one cone \(= 3.14 \times 2 \times 5 = 3.14 \times 10 = 31.4\ \text{cm}^2\).
There are 100 such cones, so total painted area \(= 100 \times 31.4 = 3140\ \text{cm}^2\).
Key concept: for painting an open cone use only \(\pi r l\) (curved surface), never the total surface area \(\pi r(l+r)\), since the base is excluded.
Hence the total painted area is 3140 cm2.
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