A small temple dome is shaped like a hemisphere of radius 3.5 m. How much area (in square meters) must be painted on the curved surface?
76.92
Given: the dome is a hemisphere of radius \(r = 3.5 \text{ m}\), and we need the curved (dome) surface area to be painted.
The curved surface of a hemisphere (the dome part only, excluding the flat base) is given by \(\text{CSA} = 2\pi r^2\).
Substitute the radius: \(\text{CSA} = 2 \times \pi \times (3.5)^2\).
Compute \((3.5)^2 = 12.25\).
Using \(\pi = 3.14\): \(\text{CSA} = 2 \times 3.14 \times 12.25\).
So \(\text{CSA} = 6.28 \times 12.25 = 76.93 \approx 76.92 \text{ m}^2\).
Hence the area to be painted on the curved surface is 76.92 square meters.
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