An electric circuit is consisting of a cell, an ammeter and a nichrome wire of length l. If the length of the wire is reduced to half (l/2), then the ammeter reading
gets doubled
The question asks how the ammeter reading changes when the length of a nichrome wire in an electric circuit is reduced to half. An ammeter measures the electric current flowing through the circuit. The current in a circuit is determined by the voltage applied and the total resistance of the circuit.
Ohm's Law states that the current (\(I\)) flowing through a conductor is directly proportional to the voltage (\(V\)) across its ends and inversely proportional to its resistance (\(R\)), provided the temperature remains constant. Mathematically, this is expressed as:
\(V = IR\)
or rearranging to find the current:
\(I = \frac{V}{R}\)
In this circuit, the cell provides a constant voltage (\(V\)). The ammeter has very low resistance, which can be considered negligible for this problem. The resistance comes mainly from the nichrome wire.
The electrical resistance (\(R\)) of a wire depends on its material, length (\(l\)), and cross-sectional area (\(A\)). The formula for resistance is:
\(R = \rho \frac{l}{A}\)
where \(\rho\) (rho) is the resistivity of the material (nichrome in this case), which is a constant for a given temperature.
Let's consider the initial and final states of the nichrome wire.
Initial State:
Final State:
The voltage (\(V\)) supplied by the cell remains constant. The new current (\(I_2\)) in the circuit with the reduced resistance is:
\(I_2 = \frac{V}{R_2}\)
Substitute the value of \(R_2\) in terms of \(R_1\):
\(I_2 = \frac{V}{R_1/2} = 2 \times \frac{V}{R_1}\)
Since \(I_1 = \frac{V}{R_1}\), we have:
\(I_2 = 2 \times I_1\)
This means the new current is twice the original current. The ammeter reading measures the current, so the ammeter reading will get doubled.
| Parameter | Initial Value | Change | Final Value |
|---|---|---|---|
| Wire Length (l) | \(l\) | Reduced to half | \(l/2\) |
| Resistance (R) | \(R_1 = \rho \frac{l}{A}\) | Reduced to half | \(R_2 = \frac{1}{2} R_1\) |
| Voltage (V) | \(V\) | Remains Constant | \(V\) |
| Current (I) | \(I_1 = \frac{V}{R_1}\) | Gets doubled | \(I_2 = \frac{V}{R_2} = 2I_1\) |
| Ammeter Reading | \(I_1\) | Gets doubled | \(I_2 = 2I_1\) |
Therefore, when the length of the nichrome wire is reduced to half, the resistance is also reduced to half. With constant voltage, the current in the circuit doubles. The ammeter reading, which measures this current, will consequently get doubled.
| Concept | Formula | Relationship with length | Relationship with Area |
|---|---|---|---|
| Resistance (R) | \(R = \rho \frac{l}{A}\) | Directly proportional (R \(\propto\) l) | Inversely proportional (R \(\propto\) 1/A) |
| Current (I) | \(I = \frac{V}{R}\) | Inversely proportional to R | Directly proportional to R |
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