An electric bulb is connected to a 110 V generator. The current is 0.2 A. What is the power of the bulb ?
22 W
This question asks us to calculate the power of an electric bulb given the voltage across it and the current flowing through it. To find the electric power, we need to use the fundamental relationship between power, voltage, and current in an electrical circuit.
Electric power is the rate at which electrical energy is transferred by an electric circuit. It is a measure of how much work is done by the electric current per unit of time. The standard unit of electric power is the Watt (W).
The power (P) dissipated by an electrical device, such as an electric bulb, is related to the voltage (V) across it and the current (I) flowing through it by the following formula:
\[P = V \times I\]
Where:
We are given the following information about the electric bulb:
Now, we can substitute these values into the formula for electric power:
\[P = V \times I\]
\[P = 110 \text{ V} \times 0.2 \text{ A}\]
\[P = 22 \text{ W}\]
So, the power of the electric bulb is 22 Watts.
Let's break down the calculation:
Let's compare our calculated power of 22 W with the given options:
Our calculated value of 22 W matches Option 3.
| Quantity | Symbol | Given Value | Unit |
|---|---|---|---|
| Voltage | V | 110 | V |
| Current | I | 0.2 | A |
| Power | P | ? | W |
| Concept | Formula | Units | Explanation |
|---|---|---|---|
| Electric Power | P = V \(\times\) I | Watts (W) | Rate of energy transfer in an electric circuit. |
| Voltage | V | Volts (V) | Electric potential difference across components. |
| Current | I | Amperes (A) | Rate of flow of electric charge. |
| Energy | E = P \(\times\) t | Joules (J) or Watt-hours (Wh) | Power multiplied by time. |
Besides P = V \(\times\) I, electric power can also be calculated using Ohm's Law, which states V = I \(\times\) R (where R is resistance). By substituting Ohm's Law into the power formula, we get alternative formulas:
These formulas can be used to calculate electric power if voltage and resistance, or current and resistance, are known instead of voltage and current. In this specific problem involving the electric bulb, we were given voltage and current, making the P = V \(\times\) I formula the most direct approach.
Two metallic wires made from copper have same length but the radius of wire 1 is half of that of wire 2. The resistance of wire 1 is R. If both the wires are joined together in series, the total resistance becomes
A parallel-plate capacitor of capacitance C 1is made using two gold plates. Another parallel-plate capacitor of capacitance C 2is made using two aluminium plates with same plate separation, and all the four plates are of same area. If ρ gand ρ aare respectively the electrical resistivity of gold and aluminium, then which one of the following relations is correct?
A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become
The r.m.s. potential difference between the red live wire and black neutral wire in Indian domestic electric supply is
An electric circuit is consisting of a cell, an ammeter and a nichrome wire of length l. If the length of the wire is reduced to half (l/2), then the ammeter reading
A metal wire of length l and diameter d has a resistance R. What would be the resistance of another wire of the same metal and of the same length but having double the diameter?
Which of the following is a bad conductor of electricity?
In general, in an alternating current circuit
The laws of electromagnetic induction have been used in the construction of a
A 220 volt and 100 watt bulb is connected to a 110 volt source. The power consumption by the bulb is
In the series combination of resistance in current electricity, which of the following is correct?