An athlete runs 8 times around a circular field of radius 7 m in 3 minutes 40 seconds. His speed (in km/h) is: (Take π = \(\frac{22}{7}\) )
The problem asks us to find the speed of an athlete in kilometers per hour (km/h) who runs around a circular field. We are given the radius of the field, the number of rounds the athlete completes, and the total time taken.
The distance covered in one round is equal to the circumference of the circular field. The formula for the circumference of a circle is \(C = 2 \pi r\).
Using the given values:
Circumference \(C = 2 \times \frac{22}{7} \times 7\) m
\(C = 2 \times 22\) m
\(C = 44\) m
So, the distance covered in one round is 44 meters.
The athlete runs 8 times around the field. The total distance covered is the distance of one round multiplied by the number of rounds.
Total Distance = Number of rounds \(\times\) Circumference
Total Distance = \(8 \times 44\) m
Total Distance = 352 m
The athlete covers a total distance of 352 meters.
The time is given in minutes and seconds. To calculate speed, it's easier to have the time in a single unit, like seconds.
Total time = 3 minutes 40 seconds
1 minute = 60 seconds
3 minutes = \(3 \times 60 = 180\) seconds
Total time in seconds = 180 seconds + 40 seconds = 220 seconds
The total time taken is 220 seconds.
Speed is calculated as Total Distance divided by Total Time.
Speed \( = \frac{\text{Total Distance}}{\text{Total Time}} \)
Speed \( = \frac{352 \text{ m}}{220 \text{ s}} \)
We can simplify this fraction:
Speed \( = \frac{352}{220} = \frac{176 \times 2}{110 \times 2} = \frac{176}{110} = \frac{88 \times 2}{55 \times 2} = \frac{88}{55} \)
Both 88 and 55 are divisible by 11:
Speed \( = \frac{88 \div 11}{55 \div 11} = \frac{8}{5} \) m/s
The speed of the athlete is \(\frac{8}{5}\) m/s.
The question asks for the speed in km/h. To convert a speed from meters per second (m/s) to kilometers per hour (km/h), we multiply by the conversion factor \(\frac{18}{5}\).
Speed in km/h \( = \text{Speed in m/s} \times \frac{18}{5} \)
Speed in km/h \( = \frac{8}{5} \times \frac{18}{5} \)
Speed in km/h \( = \frac{8 \times 18}{5 \times 5} \)
Speed in km/h \( = \frac{144}{25} \) km/h
The speed of the athlete is \(\frac{144}{25}\) km/h.
| Radius | 7 m |
| Circumference | 44 m |
| Number of Rounds | 8 |
| Total Distance | 352 m |
| Total Time | 3 min 40 sec = 220 sec |
| Speed in m/s | \(\frac{352}{220} = \frac{8}{5}\) m/s |
| Speed in km/h | \(\frac{8}{5} \times \frac{18}{5} = \frac{144}{25}\) km/h |
Based on the calculations, the speed of the athlete is \(\frac{144}{25}\) km/h.
| Concept | Formula/Conversion | Notes |
| Circumference of a Circle | \(C = 2 \pi r\) | Distance covered in one round. |
| Total Distance | \( \text{Number of rounds} \times C \) | Total path length. |
| Speed | \( \text{Distance} \div \text{Time} \) | Measure of how fast something moves. |
| Minutes to Seconds | \( \text{Minutes} \times 60 \) | Unit conversion. |
| m/s to km/h | Multiply by \(\frac{18}{5}\) | Unit conversion factor. |
| km/h to m/s | Multiply by \(\frac{5}{18}\) | Unit conversion factor. |
Speed, distance, and time are fundamental concepts in physics and mathematics used to describe motion.
Understanding how to convert between different units of speed (like m/s and km/h) is essential for solving many problems related to motion.
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