This problem involves calculating the time taken by an individual based on relative efficiency compared to another person.
Efficiency and the time taken to complete a task are inversely proportional. If someone is more efficient, they will take less time to finish the same job.
Amit is 70% more efficient than Ajay. This means Amit's efficiency is Ajay's efficiency plus 70% of Ajay's efficiency.
Mathematically:
$E_M = E_A + (70\% \times E_A)$ $E_M = E_A + (0.70 \times E_A)$ $E_M = 1.70 \times E_A$Since time is inversely proportional to efficiency ($T \propto \frac{1}{E}$), we can set up the ratio:
$\frac{T_M}{T_A} = \frac{E_A}{E_M}$Substitute the known values and the relationship between $E_M$ and $E_A$:
$\frac{T_M}{12 \text{ days}} = \frac{E_A}{1.70 \times E_A}$ $\frac{T_M}{12} = \frac{1}{1.70}$Now, solve for $T_M$:
$T_M = 12 \times \frac{1}{1.7}$ $T_M = \frac{12}{1.7}$To simplify, multiply the numerator and denominator by 10:
$T_M = \frac{120}{17}$Convert the improper fraction to a mixed number:
$120 \div 17 = 7$ with a remainder of $1$. $T_M = 7 \frac{1}{17}$ days.Amit would need $7 \frac{1}{17}$ days to finish the same painting.
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