Acceleration due to gravity on Jupiter is two and a half times that on earth. How much would a 250 kg satellite weigh (in N) on Jupiter? (acceleration due to gravity on earth = 10 m/s 2)
This question asks us to find the weight of a satellite on Jupiter, given its mass, the acceleration due to gravity on Earth, and the relationship between gravity on Jupiter and Earth.
\[\text{Weight} (W) = \text{Mass} (m) \times \text{Acceleration due to gravity} (g)\]
Step 1: Find the acceleration due to gravity on Jupiter.
We know that \(g_{jupiter} = 2.5 \times g_{earth}\). Substitute the given value for \(g_{earth}\).
\[g_{jupiter} = 2.5 \times 10 \, m/s²\]
\[g_{jupiter} = 25 \, m/s²\]
So, the acceleration due to gravity on Jupiter is 25 m/s².
Step 2: Calculate the weight of the satellite on Jupiter.
Use the formula for weight: \(W_{jupiter} = m \times g_{jupiter}\). Substitute the mass of the satellite and the calculated gravity on Jupiter.
\[W_{jupiter} = 250 \, kg \times 25 \, m/s²\]
\[W_{jupiter} = 6250 \, N\]
The weight of the 250 kg satellite on Jupiter would be 6,250 Newtons.
Let's compare our calculated weight with the given options:
| Option | Weight (N) |
|---|---|
| 1 | 10 |
| 2 | 625 |
| 3 | 6,250 |
| 4 | 100 |
Our calculated value, 6,250 N, matches Option 3.
| Concept | Formula/Value | Notes |
|---|---|---|
| Mass (\(m\)) | 250 kg | Constant value |
| Gravity on Earth (\(g_{earth}\)) | 10 m/s² | Given value |
| Gravity on Jupiter (\(g_{jupiter}\)) | \(2.5 \times g_{earth}\) | Given relationship |
| Calculated \(g_{jupiter}\) | \(2.5 \times 10 = 25\) m/s² | Step 1 result |
| Weight on Jupiter (\(W_{jupiter}\)) | \(m \times g_{jupiter}\) | Formula for weight |
| Calculated \(W_{jupiter}\) | \(250 \times 25 = 6250\) N | Step 2 result |
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