A block of metal of mass 500 g has a relative density of 2.5. What will be its apparent mass when it is fully immersed in water?
300 g
Relative density = density of metal/density of water, and density of water is 1 g/cm³.
Volume of the metal block = mass/density = 500/2.5 = 200 cm³.
Mass of water displaced = 200 × 1 = 200 g, which is the loss of apparent mass.
Apparent mass = 500 - 200 = 300 g
Check: 300 g + 200 g = 500 g, the real mass.
Hence, 300 g.
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