Calculating Train Travel Time in Seconds
This problem requires calculating the time taken for a train to travel a given distance at a specific speed. The final answer needs to be in seconds.
Given Information
- Speed of train = 45 km/h
- Distance = $\frac{4}{5}$ km
Formula
The relationship between speed, distance, and time is given by:
$Time = Distance / Speed$
Calculation Steps
-
Calculate the time in hours using the given speed and distance.
$Time (hours)$ = $\frac{\text{Distance}}{\text{Speed}}$
$Time (hours)$ = $\frac{\frac{4}{5} \text{ km}}{45 \text{ km/h}}$
$Time (hours)$ = $\frac{4}{5 \times 45}$ hours
$Time (hours)$ = $\frac{4}{225}$ hours
-
Convert the time from hours to seconds.
We know that 1 hour = 3600 seconds.
$Time (seconds)$ = $Time (hours)$ $\times$ 3600
$Time (seconds)$ = $\frac{4}{225} \times 3600$ seconds
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Simplify the expression.
$Time (seconds)$ = $4 \times \frac{3600}{225}$ seconds
$Time (seconds)$ = $4 \times 16$ seconds
$Time (seconds)$ = 64 seconds
Therefore, the train will take 64 seconds to cover the distance of $\frac{4}{5}$ km.
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Important Questions from Speed Time and Distance
A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is
Rajiv's boat can travel along the current at the 8 km/hour and against the current at the rate 6 km/hour. Find the time taken by the boat to sail 28 km in still water.
Rohit and Dinesh are 64 km apart. Rohit can walk at a speed of 15 km/hr and Dinesh at the speed of 17 km/hr. In how many hours will they meet if they are travelling towards each other?
Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively and they cross each other in 30 seconds. The ratio of their speed is:
A worker covers a distance of 81 km in 11 hours. He travels partly on foot at 4.5 km/h and partly on bicycle at 15 km/h. What is the distance covered on the cycle?
