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Question

A trader has a weighing balance that shows 1300 g for a kg. He further marks up his cost price by 15%. The net profit percentage is :

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

49.5%

Understanding the Profit Scenario

This problem involves a trader who uses two methods to increase profit: a faulty weighing balance and marking up the price. We need to calculate the overall net profit percentage achieved by the trader.

  • The trader's weighing balance shows 1300 g when the actual weight is 1000 g (1 kg). This means for every 1300 g shown, he is only giving 1000 g of the product.
  • Additionally, the trader marks up the cost price by 15%. This means he increases the price he sells at by 15% over his initial cost for the quantity he claims to sell.

Step-by-Step Profit Calculation

Let's assume a base value to make the calculation straightforward. We will assume the trader's cost price for 1000 grams (1 kg actual weight) is Rs. 100.

Step 1: Determine the Actual Quantity Given vs. Quantity Charged

The faulty balance shows 1300 g for 1000 g. When the trader sells something showing 1300 g on the scale, he is actually giving only 1000 g.

  • Actual quantity given = 1000 g
  • Quantity shown/charged for = 1300 g

This is equivalent to saying that for every 1 g shown, the actual weight is $1000/1300 = 10/13$ grams.

Step 2: Calculate the Marked Price

The trader marks up his cost price by 15%. Let's assume the cost price of 1000 g (actual) is Rs. 100.

The trader bases his marked price on the weight shown on the scale. He pretends his cost for 1000g shown is Rs 100. Then he marks it up.

  • Assumed Cost Price (for 1000 g shown) = Rs. 100
  • Mark-up percentage = 15%
  • Marked Price (MP) for 1000 g shown = Cost Price + 15% of Cost Price
  • MP = $100 + \left(\frac{15}{100} \times 100\right) = 100 + 15 = \text{Rs. } 115$

So, the marked price for 1000 g shown on the scale is Rs. 115.

Step 3: Determine the Selling Price for the Actual Quantity Sold

The trader sells 1000 g (actual weight) but charges the price for 1300 g *shown* on his scale. The price per gram shown is based on the marked price for 1000 g shown.

  • Price per gram (based on marked price for shown weight) = $\frac{\text{Marked Price for 1000 g shown}}{\text{1000 g}} = \frac{115}{1000} = \text{Rs. } 0.115 \text{ per gram shown}$
  • The trader sells 1000 g actual weight, but charges the price of 1300 g shown.
  • Selling Price (SP) for the 1000 g actual weight = Price of 1300 g shown
  • SP = $1300 \times (\text{Price per gram shown}) = 1300 \times 0.115 = \text{Rs. } 149.5$

The actual cost price for the 1000 g he sold is Rs. 100 (our initial assumption).

Step 4: Calculate the Net Profit

Net Profit = Selling Price (for actual quantity sold) - Actual Cost Price (of actual quantity sold)

  • Net Profit = Rs. 149.5 - Rs. 100 = Rs. 49.5

Step 5: Calculate the Net Profit Percentage

Net Profit Percentage = $\left(\frac{\text{Net Profit}}{\text{Actual Cost Price}}\right) \times 100$

  • Net Profit Percentage = $\left(\frac{49.5}{100}\right) \times 100 = 49.5\%$

The net profit percentage is 49.5%.

Summary Table of Profit Calculation

Item Value
Actual Weight given 1000 g
Weight shown on scale 1300 g
Assumed Actual Cost Price (for 1000g) Rs. 100
Mark-up % 15%
Marked Price (for 1000g shown) Rs. 115
Selling Price (for 1000g actual = price of 1300g shown) Rs. 149.5
Net Profit Rs. 49.5
Net Profit Percentage 49.5%

Revision Table: Key Concepts in Profit and Loss

Term Definition Formula
Cost Price (CP) The price at which an article is purchased. -
Selling Price (SP) The price at which an article is sold. -
Profit When SP > CP. Profit = SP - CP
Loss When SP < CP. Loss = CP - SP
Profit Percentage Profit expressed as a percentage of CP. $\left(\frac{\text{Profit}}{\text{CP}}\right) \times 100$
Loss Percentage Loss expressed as a percentage of CP. $\left(\frac{\text{Loss}}{\text{CP}}\right) \times 100$
Marked Price (MP) The price at which the article is listed for sale. -
Discount Reduction in the Marked Price. Discount = MP - SP
Discount Percentage Discount expressed as a percentage of MP. $\left(\frac{\text{Discount}}{\text{MP}}\right) \times 100$

Additional Information: Dealing with Faulty Weights

Problems involving faulty weighing balances are common in profit and loss. The key idea is to understand the relationship between the weight the trader claims to sell and the actual weight they provide.

If a trader uses a weight 'Wshown' instead of the actual weight 'Wactual' (where Wshown > Wactual), they are making a profit from the weighing itself. The gain from the faulty weight can be calculated as:

Gain % from faulty weight = $\left(\frac{\text{W}_{\text{shown}} - \text{W}_{\text{actual}}}{\text{W}_{\text{actual}}}\right) \times 100$

In this problem, the trader claims to sell 1300g for 1000g actual. The gain from weight alone, if there was no mark-up, would be:

Gain % = $\left(\frac{1300 - 1000}{1000}\right) \times 100 = \left(\frac{300}{1000}\right) \times 100 = 30\%$

However, the trader also applies a mark-up. When there is both a gain from faulty weight and a mark-up on price, these effects combine. A common way to think about it is that the trader gets the goods at a certain cost for the actual quantity but sells them at a price based on the charged quantity and the marked-up rate.

Let Actual CP per unit weight be $c$. Trader sells Wactual units, but charges price for Wshown units. Trader marks up price by M%. Selling Price per unit charged is $c \times (1 + M/100)$. Total SP for Wactual is $W_{\text{shown}} \times c \times (1 + M/100)$. Actual CP for Wactual is $W_{\text{actual}} \times c$. Profit % = $\left(\frac{W_{\text{shown}} \times c \times (1 + M/100) - W_{\text{actual}} \times c}{W_{\text{actual}} \times c}\right) \times 100$ Profit % = $\left(\frac{W_{\text{shown}} \times (1 + M/100) - W_{\text{actual}}}{W_{\text{actual}}}\right) \times 100$ Profit % = $\left(\frac{W_{\text{shown}}}{W_{\text{actual}}} \times (1 + M/100) - 1\right) \times 100$

Using values from the question:

Wshown = 1300, Wactual = 1000, M = 15

Profit % = $\left(\frac{1300}{1000} \times (1 + 15/100) - 1\right) \times 100$

Profit % = $\left(1.3 \times (1.15) - 1\right) \times 100$

Profit % = $(1.495 - 1) \times 100$

Profit % = $0.495 \times 100 = 49.5\%$

This formula confirms the step-by-step calculation.

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Similar Questions

  1. A shopkeeper sells an item at a profit of 15% and uses a weight which is 20% less. Find his actual profit percentage.

  2. A grocer claims that he is selling sugar at Rs. 48/kg, which costs him Rs. 50/kg, but he is giving 900 g instead of 1000 g. What will be the approximate percentage profit?

  3. A dishonest merchant sells goods at a 12.5% loss on the cost price, but uses 28 g weight instead of 36 g. What is his percentage profit or loss?

  4. A dishonest dealer marks up his goods by 50% and then gives a discount of 20% on the marked price. Apart from this, he uses a faulty balance which reads 1kg for 900 gm. What is his net profit percentage (rounded off to the nearest integer)?

  5. A dishonest shopkeeper sells mangoes at Rs. 30/kg bought at Rs. 20/kg and he is giving 800 g instead of 1 kg. The shopkeeper's actual profit percentage is:

  6. R’s weighing machine shows 400 gm when the actual weight is 350 gm. The cost price of almonds is ₹880 per kg and packets of 200 gm are made using the faulty machine. What should be the selling price (in ₹) of each packet to get a profit of 25%?

  7. A dishonest dealer sells articles at 15% loss on cost price but uses the weight of 20 g instead of 25 g. What is his profit or loss percentage?

  8. A dishonest trader says to customers that he sells his goods at a cost price, but he uses a false weight and gains 12.5% as profit. How many grams does he use to weigh 1 kg?

  9. Ramesh claims that he is selling onions at Rs. 36 per kg, which costs him Rs. 40 per kg, but he gives 800 grams instead of 1 kg. Find Ramesh's percentage gain or loss.

  10. A shopkeeper advertises for selling cloth at 7% loss. However, by using a false scale of length 1 metre he actually gains 24%. What will be the actual length he uses instead of 1 metre ?


Important Questions from Dishonest Dealings

  1. A merchant claims that he sells his goods at CP. But uses a weight of 900 g for the 1 kg weight. find his gain %

  2. A shopkeeper cheats to the extent of 9% while buying and selling fruits, by using tampered weights. His total gain in percentage is:

    A. 18.25

    B. 18.81

    C. 19.78

    D. 18.5

  3. What is the faulty weight used by a dishonest shopkeeper instead of the original weight of 1 kg to get a profit of 25%?

  4. A dishonest financier claims to be lending money at simple interest, but he includes the interest every four months for calculating the principal. If he is charging an interest of 3%, the effective rate of interest becomes:

  5. A dishonest shopkeeper claims to sell rice at the cost price of ₹95 per kg, but the weight he uses has 1 kg written on it, while it actually weighs 950 g. The profit he thus earns on selling rice having an actual weight of 95 kg rice is:

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