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Question

A dishonest dealer defrauds to the extent of x% in buying as well as selling his goods by using faulty weight. What will be the gain percent on his outlay?

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

None of these

Understanding the Problem: Dishonest Dealer and Faulty Weights

This problem involves a dealer who uses faulty weights to cheat customers during both the buying and selling process. The cheating percentage is given as \(x\%\) in both transactions. We need to find the overall gain percentage the dealer makes on their initial investment (outlay).

Impact of Faulty Weight in Buying

When the dealer buys goods, they use a faulty weight to get more quantity than they pay for. If they defraud by \(x\%\) in buying, it means for every 100 units of weight they are supposed to get according to the payment, they actually receive \(100 + x\) units of weight. In other words, they pay the price of 100 units but receive \(100+x\) actual units.

Let's assume the true cost price per unit of weight is \(C\). When the dealer buys, they pay for 100 units of weight, costing \(100C\). However, they receive \(100+x\) actual units of weight. Therefore, the effective cost price (CP) for the dealer for \(100+x\) actual units is \(100C\).

The effective CP per actual unit of weight is: \( \text{Effective CP} = \frac{\text{Total Cost}}{\text{Actual Quantity Received}} = \frac{100C}{100+x} \) We can assume the true cost price \(C=1\) for simplicity, as the gain is solely due to faulty weights. \( \text{Effective CP per actual unit} = \frac{100}{100+x} \)

Impact of Faulty Weight in Selling

When the dealer sells goods, they use a faulty weight to give less quantity than they charge for. If they defraud by \(x\%\) in selling, it means for every 100 units of weight they are supposed to sell according to the charge, they actually give \(100 - x\) units of weight. In other words, they charge the price of 100 units but give \(100-x\) actual units.

Let's assume the true selling price per unit of weight is \(S\). When the dealer sells, they give \(100-x\) actual units but charge the price of 100 units, which is \(100S\). Therefore, the effective selling price (SP) for the dealer for \(100-x\) actual units is \(100S\).

The effective SP per actual unit of weight is: \( \text{Effective SP} = \frac{\text{Total Revenue}}{\text{Actual Quantity Sold}} = \frac{100S}{100-x} \) Again, assume the true selling price \(S=1\) for simplicity (or assume \(S=C=1\)). \( \text{Effective SP per actual unit} = \frac{100}{100-x} \)

Calculating the Total Gain Percentage

The dealer's gain comes from the difference between the effective selling price and the effective cost price per unit of actual weight. The gain percentage is calculated on the effective cost price (outlay).

Gain per actual unit = Effective SP - Effective CP \( \text{Gain} = \frac{100}{100-x} - \frac{100}{100+x} \) \( \text{Gain} = 100 \left( \frac{1}{100-x} - \frac{1}{100+x} \right) \) \( \text{Gain} = 100 \left( \frac{(100+x) - (100-x)}{(100-x)(100+x)} \right) \) \( \text{Gain} = 100 \left( \frac{100+x - 100+x}{10000 - x^2} \right) \) \( \text{Gain} = 100 \left( \frac{2x}{10000 - x^2} \right) = \frac{200x}{10000 - x^2} \)

Gain Percentage = \( \frac{\text{Gain}}{\text{Effective CP}} \times 100 \) \( \text{Gain } \% = \frac{\frac{200x}{10000 - x^2}}{\frac{100}{100+x}} \times 100 \) \( \text{Gain } \% = \frac{200x}{(100-x)(100+x)} \times \frac{100+x}{100} \times 100 \) \( \text{Gain } \% = \frac{200x}{100-x} \times \frac{100}{100} \) \( \text{Gain } \% = \frac{200x}{100-x} \)

So, the gain percent on his outlay is \( \left( \frac{200x}{100-x} \right)\%\). Note: Some interpretations of "defrauds to the extent of x%" lead to \( \left( 2x + \frac{x^2}{100} \right)\% \), but the phrasing with faulty weights typically implies the error is in the weight measurement itself, leading to the calculation above.

Comparing with Options

Let's compare our derived gain percentage formula \( \left( \frac{200x}{100-x} \right)\% \) with the given options:

  1. \(2x\%\)
  2. \( \left( {\frac{{10}}{x} + {x^2}} \right)\% \)
  3. None of these
  4. \( \left( {x + \frac{{{x^2}}}{{100}}} \right)\% \)

Our calculated gain percentage \(\left( \frac{200x}{100-x} \right)\%\) does not match options 1, 2, or 4. Therefore, based on the standard interpretation of cheating using faulty weights, the correct answer is "None of these".

Fraud Type Impact on Dealer
Buying (faulty weight) Gets more quantity for the price paid. Effective CP per unit decreases.
Selling (faulty weight) Gives less quantity for the price charged. Effective SP per unit increases.

Conclusion

By defrauding \(x\%\) in both buying and selling using faulty weights, the dealer achieves a total gain percentage on outlay of \( \left( \frac{200x}{100-x} \right)\%\). As this result is not provided in options 1, 2, or 4, the correct choice is "None of these".

Revision Table: Dishonest Dealer Calculation

Concept Effect of \(x\%\) Fraud Formula/Calculation
Effective CP per actual unit (Buying) Pays for 100 units, gets \(100+x\) units actual. \( \frac{\text{Price of 100 units}}{\text{Actual quantity } (100+x)} = \frac{100}{100+x} \) (assuming price per unit = 1)
Effective SP per actual unit (Selling) Gives \(100-x\) units actual, charges for 100 units. \( \frac{\text{Price of 100 units}}{\text{Actual quantity } (100-x)} = \frac{100}{100-x} \) (assuming price per unit = 1)
Total Gain % Profit based on Effective CP. \( \left( \frac{\text{Effective SP} - \text{Effective CP}}{\text{Effective CP}} \right) \times 100 = \left( \frac{\frac{100}{100-x} - \frac{100}{100+x}}{\frac{100}{100+x}} \right) \times 100 = \frac{200x}{100-x}\% \)

Additional Information: Faulty Weight Problems

Faulty weight problems are common in profit and loss calculations. They usually involve the dealer cheating either the seller (while buying) or the buyer (while selling), or both.

  • Cheating while buying: The dealer gets more quantity than intended for the price paid. This reduces the effective cost price per unit for the dealer. If the scale shows 1000g but gives \(1000(1+x/100)\)g, the dealer pays for 1000g but gets \(1000(1+x/100)\)g.
  • Cheating while selling: The dealer gives less quantity than intended for the price charged. This increases the effective selling price per unit for the dealer. If the scale shows 1000g but gives \(1000(1-x/100)\)g, the dealer charges for 1000g but gives \(1000(1-x/100)\)g.
  • The percentage \(x\%\) can be applied to the weight itself (e.g., the weight measures \(100 \pm x\) instead of 100) or to the value obtained/given relative to the price paid/charged. The wording "defrauds to the extent of x% by using faulty weight" most commonly implies the percentage error is in the weight delivered/received relative to the stated weight.
  • The total gain percentage calculation combines these two effects. The gain is always calculated on the effective cost price (the actual cost incurred to acquire the goods).
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Similar Questions

  1. A dishonest dealer sells the goods at 7% loss on cost price but uses 18% less weight. What is his percentage of profit? (Correct to 2 decimal places)

  2. A milkman buys milk at Rs. 25 per litre and adds 1/4 of water to it and sells the mixture at Rs. 26 per litre. His gain (in %) is?

  3. R’s weighing machine shows 400 gm when the actual weight is 350 gm. The cost price of almonds is ₹880 per kg and packets of 200 gm are made using the faulty machine. What should be the selling price (in ₹) of each packet to get a profit of 25%?

  4. A trader has a weighing balance that shows 1300 g for a kg. He further marks up his cost price by 15%. The net profit percentage is :

  5. A dishonest trader says to customers that he sells his goods at a cost price, but he uses a false weight and gains 12.5% as profit. How many grams does he use to weigh 1 kg?

  6. A shopkeeper advertises for selling cloth at 7% loss. However, by using a false scale of length 1 metre he actually gains 24%. What will be the actual length he uses instead of 1 metre ?

  7. Ramesh claims that he is selling onions at Rs. 36 per kg, which costs him Rs. 40 per kg, but he gives 800 grams instead of 1 kg. Find Ramesh's percentage gain or loss.

  8. A dishonest dealer marks up his goods by 50% and then gives a discount of 20% on the marked price. Apart from this, he uses a faulty balance which reads 1kg for 900 gm. What is his net profit percentage (rounded off to the nearest integer)?

  9. A dishonest dealer sells articles at 15% loss on cost price but uses the weight of 20 g instead of 25 g. What is his profit or loss percentage?

  10. A shopkeeper sells an item at a profit of 15% and uses a weight which is 20% less. Find his actual profit percentage.


Important Questions from Dishonest Dealings

  1. A shopkeeper uses a weight of 460 grams instead of 500 grams and sells the articles at their cost price, what is his profit percentage?

  2. A trader sells an article at 20 percent profit. If he buys it at half of the cost price and sells at the same selling price as before, then what will be the profit percentage?

  3. A dishonest shopkeeper sells sugar at a rate of Rs. 45 per kg. The cost price of the sugar is Rs. 40 per kg. Even after doing this, he tries to increase his profit by removing 100 gm from each packet of 1 kg. What is the gain percent of the shopkeeper?

  4. A dishonest dealer sells the goods at 7% loss on cost price but uses 18% less weight. What is his percentage of profit? (Correct to 2 decimal places)

  5. A shopkeeper cheats to the extent of 11% while buying and selling fruits, by using tampered weights. His total gain in percentage is.

    A. 23.25

    B. 23.21

    C. 24.71

    C. 23.5

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