A sum of money is divided among A, B, and C so that A gets twice as much as B and B gets three times as much as C. If the total sum is ₹720, how much does C get?
₹72
Let C's share be \(x\). Then B gets three times C, so B = \(3x\), and A gets twice B, so A = \(2 \times 3x = 6x\).
The total of the three shares equals ₹720: \(6x + 3x + x = 10x = 720\).
Solving, \(x = \frac{720}{10} = 72\).
Hence, C gets ₹72.
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