A sum of money invested for 2 years and 9 months at the rate of 8% simple interest per annum became Rs. 732 at the end of the period. What was the sum that was initially invested?
Rs. 600
The problem asks us to find the original amount of money invested, also known as the principal, given the final amount received after a certain period at a specific simple interest rate. We are given the final amount (Principal + Simple Interest), the time period, and the annual simple interest rate.
Simple interest is calculated only on the initial principal amount. The formulas we need are:
Combining these, we can also write the Amount formula as:
$ \text{A} = \text{P} + \frac{\text{P} \times \text{R} \times \text{T}}{100} $
or
$ \text{A} = \text{P} \left(1 + \frac{\text{R} \times \text{T}}{100}\right) $
We are given the following values:
We need to find the Principal (P).
The time is given in years and months. We need to convert the entire time period into years to use it in the formula. There are 12 months in a year.
9 months = $ \frac{9}{12} $ years = $ \frac{3}{4} $ years = 0.75 years
Total Time (T) = 2 years + 0.75 years = 2.75 years
We use the formula for the Amount: $ \text{A} = \text{P} \left(1 + \frac{\text{R} \times \text{T}}{100}\right) $
Substitute the given values into the formula:
$ 732 = \text{P} \left(1 + \frac{8 \times 2.75}{100}\right) $
First, calculate the term inside the parenthesis:
$ 8 \times 2.75 = 22 $
$ \frac{8 \times 2.75}{100} = \frac{22}{100} = 0.22 $
Now, substitute this back into the equation:
$ 732 = \text{P} (1 + 0.22) $
$ 732 = \text{P} (1.22) $
To find P, divide the Amount by 1.22:
$ \text{P} = \frac{732}{1.22} $
To simplify the division, we can multiply both the numerator and denominator by 100 to remove the decimal:
$ \text{P} = \frac{732 \times 100}{1.22 \times 100} = \frac{73200}{122} $
Now, perform the division:
$ 73200 \div 122 $
We can see that $ 122 \times 6 = 732 $. Therefore, $ 122 \times 600 = 73200 $.
$ \text{P} = 600 $
So, the initial sum invested (Principal) was Rs. 600.
Let's check if a principal of Rs. 600 invested for 2.75 years at 8% simple interest per annum results in a final amount of Rs. 732.
$ \text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100} = \frac{600 \times 8 \times 2.75}{100} $
$ \text{SI} = \frac{600 \times 22}{100} = 6 \times 22 = 132 $
Simple Interest = Rs. 132
Amount = Principal + Simple Interest = $ 600 + 132 = 732 $
This matches the given amount, so our calculated principal is correct.
| Step | Description | Calculation |
|---|---|---|
| 1 | Convert Time to Years | $ 2 \text{ years} + \frac{9}{12} \text{ years} = 2 + 0.75 = 2.75 \text{ years} $ |
| 2 | Use Amount Formula | $ \text{A} = \text{P} \left(1 + \frac{\text{R} \times \text{T}}{100}\right) $ |
| 3 | Substitute Values | $ 732 = \text{P} \left(1 + \frac{8 \times 2.75}{100}\right) $ |
| 4 | Simplify Expression | $ 732 = \text{P} \left(1 + \frac{22}{100}\right) = \text{P} (1 + 0.22) = \text{P} (1.22) $ |
| 5 | Solve for P | $ \text{P} = \frac{732}{1.22} = \frac{73200}{122} = 600 $ |
The sum that was initially invested was Rs. 600.
| Term | Definition | Symbol |
|---|---|---|
| Principal | The initial amount of money invested or borrowed. | P |
| Simple Interest | Interest calculated only on the principal amount. | SI |
| Rate of Interest | The percentage at which interest is charged or earned per year. | R |
| Time | The duration for which the money is invested or borrowed, usually in years. | T |
| Amount | The total sum at the end of the time period, including principal and interest. | A |
Understanding simple interest is fundamental before moving to compound interest. Here are some key points:
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