A sum of money was invested at the rate of 7.5% simple interest per annuum for 4 years. If the investments were for 5 years, the interest earned would have been Rs. 375 more. What was the initial sum invested?
Rs. 5,000
This question deals with simple interest earned on an investment. Simple interest is calculated only on the principal amount. The formula for simple interest is:
\( \text{SI} = \frac{P \times R \times T}{100} \)
Where:
The problem provides us with the interest rate, two different time periods for investment, and the difference in the simple interest earned between these two periods. We need to find the initial sum invested, which is the Principal (\(P\)).
Let the initial sum invested be \(P\) (in Rupees).
The given Rate of Interest is \(R = 7.5\%\) per annum.
Time period, \(T_1 = 4\) years.
Simple Interest earned in 4 years, \(\text{SI}_1\):
\( \text{SI}_1 = \frac{P \times R \times T_1}{100} = \frac{P \times 7.5 \times 4}{100} \)
\( \text{SI}_1 = \frac{30P}{100} \)
Time period, \(T_2 = 5\) years.
Simple Interest earned in 5 years, \(\text{SI}_2\):
\( \text{SI}_2 = \frac{P \times R \times T_2}{100} = \frac{P \times 7.5 \times 5}{100} \)
\( \text{SI}_2 = \frac{37.5P}{100} \)
The problem states that if the investment were for 5 years instead of 4 years, the interest earned would have been Rs. 375 more. This means the difference between the simple interest earned in 5 years (\(\text{SI}_2\)) and the simple interest earned in 4 years (\(\text{SI}_1\)) is Rs. 375.
\( \text{SI}_2 - \text{SI}_1 = 375 \)
Substitute the expressions for \(\text{SI}_1\) and \(\text{SI}_2\):
\( \frac{37.5P}{100} - \frac{30P}{100} = 375 \)
Combine the terms on the left side:
\( \frac{(37.5 - 30)P}{100} = 375 \)
\( \frac{7.5P}{100} = 375 \)
Now, solve for \(P\). Multiply both sides by 100:
\( 7.5P = 375 \times 100 \)
\( 7.5P = 37500 \)
Divide both sides by 7.5:
\( P = \frac{37500}{7.5} \)
To make the division easier, we can multiply the numerator and denominator by 10 to remove the decimal:
\( P = \frac{375000}{75} \)
Now, perform the division:
\( P = 5000 \)
So, the initial sum invested was Rs. 5,000.
Let's verify the difference:
The calculated difference matches the value given in the problem (Rs. 375), confirming our calculated principal amount is correct.
| Step | Description | Calculation |
|---|---|---|
| 1 | Identify Variables | R = 7.5%, T1 = 4 years, T2 = 5 years, SI2 - SI1 = 375 |
| 2 | Write SI Formula | \( \text{SI} = \frac{P \times R \times T}{100} \) |
| 3 | Calculate SI1 | \( \text{SI}_1 = \frac{P \times 7.5 \times 4}{100} = \frac{30P}{100} \) |
| 4 | Calculate SI2 | \( \text{SI}_2 = \frac{P \times 7.5 \times 5}{100} = \frac{37.5P}{100} \) |
| 5 | Set up Difference Equation | \( \text{SI}_2 - \text{SI}_1 = 375 \) |
| 6 | Solve for P | \( \frac{37.5P}{100} - \frac{30P}{100} = 375 \implies \frac{7.5P}{100} = 375 \implies P = \frac{37500}{7.5} = 5000 \) |
| Term | Definition | Formula |
|---|---|---|
| Principal (P) | The initial amount of money invested or borrowed. | - |
| Rate (R) | The percentage at which interest is calculated per annum. | - |
| Time (T) | The duration for which the money is invested or borrowed, usually in years. | - |
| Simple Interest (SI) | Interest calculated only on the principal amount. | \( \text{SI} = \frac{P \times R \times T}{100} \) |
| Amount (A) | The total sum after adding interest to the principal. | \( A = P + \text{SI} \) |
It's important to distinguish between simple interest and compound interest, although this problem specifically uses simple interest.
Understanding which type of interest is being used is crucial for solving problems correctly.
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