A sum of ₹25,000 is invested at 2% per annum compounded annually. Find the compound interest after 2 years.
₹1,010
Principal \(P = 25000\), Rate \(r = 2\%\), Time \(n = 2\) years.
Amount after 2 years: \(A = P\left(1 + \frac{r}{100}\right)^n = 25000 \times (1.02)^2 = 25000 \times 1.0404 = 26010\).
Compound Interest = \(A - P = 26010 - 25000 = 1010\).
Hence, the compound interest after 2 years is ₹1,010.
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