The problem requires finding how many small cones can be made by melting a larger sphere. This involves comparing the volumes of the sphere and the cones.
Given the sphere's diameter is 24 cm, its radius (R) is half of that:
Radius of sphere, \( R = \frac{24 \text{ cm}}{2} = 12 \text{ cm} \)
The volume of a sphere is calculated using the formula \( V_{sphere} = \frac{4}{3}\pi R^3 \).
Substituting the radius:
\( V_{sphere} = \frac{4}{3}\pi (12 \text{ cm})^3 \)
\( V_{sphere} = \frac{4}{3}\pi (1728 \text{ cm}^3) \)
\( V_{sphere} = 4 \times \pi \times 576 \text{ cm}^3 \)
\( V_{sphere} = 2304\pi \text{ cm}^3 \)
Each small cone has a base radius (r) of 4 cm and a height (h) of 9 cm.
The volume of a cone is calculated using the formula \( V_{cone} = \frac{1}{3}\pi r^2 h \).
Substituting the given values:
\( V_{cone} = \frac{1}{3}\pi (4 \text{ cm})^2 (9 \text{ cm}) \)
\( V_{cone} = \frac{1}{3}\pi (16 \text{ cm}^2) (9 \text{ cm}) \)
\( V_{cone} = \pi \times 16 \text{ cm}^2 \times 3 \text{ cm} \)
\( V_{cone} = 48\pi \text{ cm}^3 \)
To find the total number of cones obtained, divide the volume of the sphere by the volume of one cone.
Number of cones \( N = \frac{V_{sphere}}{V_{cone}} \)
\( N = \frac{2304\pi \text{ cm}^3}{48\pi \text{ cm}^3} \)
\( N = \frac{2304}{48} \)
\( N = 48 \)
Therefore, 48 cones will be obtained.
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