A shopkeeper offers the following schemes on toys of the same marked price. (A) Successive discounts of 34% and 37% on any number of toys bought. (B) Successive discounts of 36%, 15% and 14% on any number of toys bought. (C) 33% discount on the first 6 toys and 9% discount on each toy thereon. (D) 3 toys free of cost on buying 9 toys. A customer wants to buy 9 toys. Which of the above schemes is the least beneficial to her?
C
Let each toy have a marked price of 100 units, so 9 toys have a total marked price of 900 units. The least beneficial scheme is the one that leaves the highest final cost.
Scheme A: successive discounts of 34% and 37% give a net factor of \(0.66 \times 0.63 = 0.4158\), so the cost for 9 toys is \(900 \times 0.4158 = 374.22\).
Scheme B: successive discounts of 36%, 15% and 14% give \(0.64 \times 0.85 \times 0.86 = 0.46784\), so the cost is \(900 \times 0.46784 = 421.06\).
Scheme C: 6 toys at 33% discount cost \(6 \times 100 \times 0.67 = 402\), and the remaining 3 toys at 9% discount cost \(3 \times 100 \times 0.91 = 273\), giving a total of \(402 + 273 = 675\).
Scheme D: paying for 9 toys but effectively receiving 12 (9 plus 3 free) means the customer pays 900 for 12 toys; for the 9 toys she keeps in the comparison she still pays 900 for the purchase, the highest outlay only if she needed exactly 9. Comparing the cost of 9 toys, Scheme C at 675 is far above the true-discount schemes A (374.22) and B (421.06).
Among the schemes, Scheme C leaves the greatest cost for buying 9 toys, so it is the least beneficial to the customer.
Hence, the least beneficial scheme is C.
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