This solution explains how to find the original labelled rate of a laptop when successive discounts are applied and the final sale price is known.
Let the original labelled rate of the laptop be denoted by L.
Two discounts are offered:
The final sale price is given as ₹18,000.
After a 25% discount, the price becomes:
Price = $L \times (1 - \frac{25}{100}) = L \times (1 - 0.25) = L \times 0.75$
An additional 20% discount is applied to the already discounted price:
Final Price = $(L \times 0.75) \times (1 - \frac{20}{100})$
Final Price = $(L \times 0.75) \times (1 - 0.20) = L \times 0.75 \times 0.80$
Calculate the overall effect of the discounts:
Combined Multiplier = $0.75 \times 0.80 = 0.60$
This means the final sale price is 60% of the labelled rate.
We know the final sale price is ₹18,000:
$L \times 0.60 = 18000$
Rearrange the equation to find L:
$L = \frac{18000}{0.60}$
$L = \frac{18000}{6/10}$
$L = 18000 \times \frac{10}{6}$
$L = 3000 \times 10$
$L = 30000$
Therefore, the labelled rate of the laptop was ₹30,000.
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