The problem involves calculating the total percentage gain when a shopkeeper uses tampered weights to cheat by 8% during both buying and selling.
We can treat the cheating in buying and selling as two separate instances of percentage gain applied sequentially.
When buying, the shopkeeper cheats by 8%. This means he gets 8% more quantity than he pays for. This effectively results in a gain of 8%.
Buying Gain = $8\%$
When selling, the shopkeeper cheats by 8%. This means he gives 8% less quantity than the customer pays for. This effectively results in a gain of 8% on the selling price.
Selling Gain = $8\%$
To find the total gain percentage when two successive percentage gains (or losses) occur, we use the formula:
$ \text{Total Gain \%} = x + y + \frac{xy}{100} $
Where $x$ is the first gain percentage and $y$ is the second gain percentage.
In this case, $x = 8\%$ and $y = 8\%$.
$ \text{Total Gain \%} = 8 + 8 + \frac{8 \times 8}{100} $
$ \text{Total Gain \%} = 16 + \frac{64}{100} $
$ \text{Total Gain \%} = 16 + 0.64 $
$ \text{Total Gain \%} = 16.64\% $
The shopkeeper's total gain percentage is 16.64%.
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