A series is given with one term missing. Select the correct alternative from the given ones that will complete the series. 1, 0.25, 1/9, ?, 0.04, 1/36
0.0625
Rewriting the decimals as fractions gives \(1, \tfrac{1}{4}, \tfrac{1}{9}, ?, \tfrac{1}{25}, \tfrac{1}{36}\). The denominators are perfect squares \(1^2, 2^2, 3^2, ?, 5^2, 6^2\), so the general term is \(\tfrac{1}{n^2}\).
The missing term is \(\tfrac{1}{4^2} = \tfrac{1}{16} = 0.0625\).
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