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Question

A river 6 m deep and 35 m wide is flowing at the rate of 2.5 km/h, the amount of water that runs into the sea per minute is:

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

8750 m3

Calculating River Water Volume Per Minute

This problem asks us to determine the volume of water that flows from a river into the sea each minute, given the river's dimensions and flow rate. We are provided with the depth, width, and the speed at which the water flows.

Here are the given parameters:

  • River Depth: 6 m
  • River Width: 35 m
  • Flow Rate: 2.5 km/h

To find the volume of water flowing per minute, we need to calculate the volume of a section of the river water that passes a fixed point in one minute. Imagine this section as a rectangular prism. Its dimensions would be the width of the river, the depth of the river, and the distance the water travels in one minute (which is the flow rate converted to meters per minute).

First, let's convert the flow rate from kilometers per hour (km/h) to meters per minute (m/min).

  • 1 kilometer (km) = 1000 meters (m)
  • 1 hour (h) = 60 minutes (min)

So, the flow rate in m/min is calculated as:

\[ \text{Flow Rate (m/min)} = \left(2.5 \text{ } \frac{\text{km}}{\text{h}}\right) \times \left(\frac{1000 \text{ m}}{1 \text{ km}}\right) \times \left(\frac{1 \text{ h}}{60 \text{ min}}\right) \]

\[ \text{Flow Rate (m/min)} = \frac{2.5 \times 1000}{60} \text{ } \frac{\text{m}}{\text{min}} \]

\[ \text{Flow Rate (m/min)} = \frac{2500}{60} \text{ } \frac{\text{m}}{\text{min}} \]

\[ \text{Flow Rate (m/min)} = \frac{250}{6} \text{ } \frac{\text{m}}{\text{min}} = \frac{125}{3} \text{ } \frac{\text{m}}{\text{min}} \]

Now that we have the flow rate in meters per minute, we can calculate the volume of water flowing into the sea per minute. The volume is the product of the river's width, depth, and the distance the water travels in one minute (flow rate in m/min).

\[ \text{Volume per minute} = \text{Width} \times \text{Depth} \times \text{Flow Rate (m/min)} \]

\[ \text{Volume per minute} = 35 \text{ m} \times 6 \text{ m} \times \frac{125}{3} \text{ } \frac{\text{m}}{\text{min}} \]

Let's perform the multiplication:

\[ \text{Volume per minute} = (35 \times 6 \times \frac{125}{3}) \text{ } \text{m}^3/\text{min} \]

We can simplify the calculation by dividing 6 by 3:

\[ \text{Volume per minute} = (35 \times 2 \times 125) \text{ } \text{m}^3/\text{min} \]

\[ \text{Volume per minute} = (70 \times 125) \text{ } \text{m}^3/\text{min} \]

Now, let's calculate $70 \times 125$:

\[ 70 \times 125 = 70 \times (100 + 25) = (70 \times 100) + (70 \times 25) = 7000 + 1750 = 8750 \]

So, the volume of water that runs into the sea per minute is $8750 \text{ m}^3$.

Comparing this result with the given options:

Option Volume
1 $8570 \text{ m}^3$
2 $7850 \text{ m}^3$
3 $7580 \text{ m}^3$
4 $8750 \text{ m}^3$

Our calculated volume matches Option 4.

Revision Table: Key Concepts

Concept Description Formula Used
Volume Flow Rate The volume of fluid passing through a cross-sectional area per unit time. Area × Velocity
Unit Conversion Converting a measurement from one unit to another (e.g., km/h to m/min). Using conversion factors ($1 \text{ km} = 1000 \text{ m}$, $1 \text{ h} = 60 \text{ min}$)
Volume of a Prism The amount of space occupied by a 3D object with a constant cross-sectional area. Base Area × Height (or Length)

Additional Information: Understanding River Flow

The flow of a river is a complex phenomenon, but for simplified calculations like this, we treat the river channel as having a uniform rectangular cross-section. The flow rate represents the average speed of the water. The volume flow rate is a crucial concept in hydrology and environmental science, helping us understand water resources, flood dynamics, and the transport of substances within rivers. The unit m³/min (cubic meters per minute) is a standard unit for expressing volume flow rate.

In this specific problem, we calculated the volume of water that flows past a point (like the river mouth entering the sea) every minute. This volume is essentially the volume of a slug of water whose length is the distance the water travels in one minute, and whose cross-sectional area is the area of the river channel ($35 \text{ m} \times 6 \text{ m}$).

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Similar Questions

  1. A man takes 15 minutes to row 16 km downstream, which is 25% less than the time he takes to row the same distance upstream. How many kilometres can the man row in an hour in still water? (Rounded off to nearest whole number)

  2. To go a distance of 144 km upstream, a rower takes 12 hours while it takes her only 9 hours to row the same distance downstream. What is the speed of the stream?

  3. A boat covers a distance of 80 km downstream in 8 h while it takes 10 h to cover the same distance upstream. What is the speed (in km/h) of the boat in still water?

  4. Dharmendra can row 80 km upstream and 110 km downstream in 13 hours. Also, he can row 60 km upstream and 88 km downstream in 10 hours. What is the speed (in km/h) of the current?

  5. A man can row 10 km/h in still water. When the river is running at a speed of 4.5 km/h, then it takes him 2 h to row to a place and comes back to the initial point . How far is the place (in km) (rounded off to two decimal places)?

  6. A boat covers 35 km downstream in 2 h and covers the same distance upstream in 7 h. Find the speed (in km/h) of the boat in still water.

  7. A motorboat whose speed is 20 km/h in still water takes 30 minutes more to go 24 km upstream than to cover the same distance downstream. If the speed of the boat in still water is increased by 2 km/h, then how much time will it take to go 39 km downstream and 30 km upstream?
  8. A boatman can row his boat in still water at a speed of 9 km/h. He can also row 44 km downstream and 35 km upstream in 9 hours. How much time (in hours) will he take to row 33 km downstream and 28 km upstream?
  9. X, Y are two points in a river. Points P and Q divide the straight line XY into three equal parts. The river flows along XY and the time taken by a boat to row from X to Q and from Y to Q are in the ratio 4 : 5. The ratio of the speed of the boat downstream to that of the river current is equal to:

  10. A boat goes 27 km upstream and 33 km downstream in 6 hours. In the same time it can go 36 km upstream and 22 km downstream. How much time will it take to go 36 km upstream and 44 km downstream?


Important Questions from Boat and River

  1. The speed of a ship in still water is 5 km/hr and the speed of the stream is 2 km/hr. Rohan rows to place at a distance of 21 km and comes back to the starting point. The total time taken by him is:

  2. The speed of a boat in still water is 9 km/hr and the speed of stream is 3 km/hr. The difference between the upstream speed and downstream speed will be:

  3. A boat can go 10 km upstream and 11 km downstream in a total time of 52 minutes, If the speed of the stream is 5 km/h, then what is the speed (in km/h) of the boat when going downstream?

  4. The upstream speed of the boat is 40 km/hr and the speed of the boat in still water is 55 km/hr. What is the downstream speed of the boat?

    A. 75 km/hr

    B. 70 km/hr

    C. 60 km/hr

    D. 65 km/hr
  5. A boat moving upstream takes 8 hours 48 minutes to cover a distance while it takes 4 hours to return to the starting point, downstream. What is the ratio of the speed of boat in still water to that of water current?

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