A boat sails 15 km of a river towards upstream in 5 hours. How long (in hours) will it take to cover the same distance downstream, if the speed of river is one-fourth the speed of the boat in still water?
3
When a boat travels in a river, its speed relative to the land is affected by the river's current. There are two main scenarios:
The problem states that the boat sails 15 km upstream in 5 hours.
The formula for speed is:
\( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \)
Using this, we can find the upstream speed:
\( \text{Upstream Speed} = \frac{15 \text{ km}}{5 \text{ hours}} = 3 \text{ km/hr} \)
Let:
So, the upstream speed is also given by \( S_b - S_r \).
Therefore, we have the equation:
\( S_b - S_r = 3 \quad \ldots(1) \)
The problem also states that the speed of the river is one-fourth the speed of the boat in still water.
This gives us another equation:
\( S_r = \frac{1}{4} S_b \quad \ldots(2) \)
Now we can substitute equation (2) into equation (1):
\( S_b - \left(\frac{1}{4} S_b\right) = 3 \)
\( S_b - \frac{1}{4} S_b = 3 \)
Combine the terms involving \( S_b \):
\( \left(1 - \frac{1}{4}\right) S_b = 3 \)
\( \left(\frac{4-1}{4}\right) S_b = 3 \)
\( \frac{3}{4} S_b = 3 \)
Solve for \( S_b \):
\( S_b = 3 \times \frac{4}{3} \)
\( S_b = 4 \text{ km/hr} \)
Now substitute the value of \( S_b \) back into equation (2) to find \( S_r \):
\( S_r = \frac{1}{4} S_b = \frac{1}{4} \times 4 \)
\( S_r = 1 \text{ km/hr} \)
The downstream speed is the sum of the boat's speed in still water and the river's speed.
\( \text{Downstream Speed} = S_b + S_r \)
Using the values we found for \( S_b \) and \( S_r \):
\( \text{Downstream Speed} = 4 \text{ km/hr} + 1 \text{ km/hr} \)
\( \text{Downstream Speed} = 5 \text{ km/hr} \)
The question asks how long it will take to cover the same distance downstream. The distance is 15 km.
Using the formula \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \):
\( \text{Downstream Time} = \frac{15 \text{ km}}{\text{Downstream Speed}} \)
\( \text{Downstream Time} = \frac{15 \text{ km}}{5 \text{ km/hr}} \)
\( \text{Downstream Time} = 3 \text{ hours} \)
Therefore, it will take 3 hours to cover the same distance downstream.
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