Question : Is \(r^n\) less than 1, where \(r\) is a real number and \(n\) is a natural number ?
Statement-I : \(0 < r^2 < 1\)
Statement-II : \(0 < r^3 < 2\)
Which one of the following is correct in respect of the above Question and the Statements ?
Statement-I provides the inequality \(0 < r^2 < 1\). This implies that the real number \(r\) must lie strictly between \(-1\) and \(1\), and \(r\) cannot be \(0\). So, \(-1 < r < 1\) and \(r \neq 0\).
We need to determine if \(r^n < 1\) is always true under this condition, where \(n\) is a natural number.
Since \(r^n < 1\) is true for all values of \(r\) satisfying Statement-I and for all natural numbers \(n\), Statement-I alone is sufficient to answer the question affirmatively.
Statement-II provides the inequality \(0 < r^3 < 2\). By taking the cube root, we find \(0 < r < \sqrt[3]{2}\). Since \(\sqrt[3]{2}\) is approximately \(1.26\), this means \(r\) is a positive number less than approximately \(1.26\).
This condition alone does not guarantee that \(r^n < 1\). Consider \(r = 1.1\). This value satisfies \(0 < r < \sqrt[3]{2}\) because \(1.1^3 = 1.331\), which falls within the range \((0, 2)\).
However, if \(n=1\), then \(r^n = 1.1^1 = 1.1\). Since \(1.1\) is not less than \(1\), the condition \(r^n < 1\) is not met.
Therefore, Statement-II alone is not sufficient to answer the question.
To determine if both statements together are sufficient, we combine their conditions:
If \(0 < r < 1\), then for any natural number \(n\), \(r^n\) will always be positive and less than \(1\). For example, \((0.5)^n\) is always less than \(1\) for \(n \ge 1\).
Thus, using both statements together, we can definitively answer that \(r^n < 1\).
Statement-I alone is sufficient to answer the question (\(r^n < 1\)). Statement-II alone is not sufficient. Therefore, the question can be answered using one of the statements alone, but not using the other statement alone. This corresponds to Option A.
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