Question : Is \(r^n\) less than 1, where \(r\) is a real number and \(n\) is a natural number ?
Statement-I : \(0 < r^2 < 1\)
Statement-II : \(0 < r^3 < 2\)
Which one of the following is correct in respect of the above Question and the Statements ?
Statement-I provides the inequality \(0 < r^2 < 1\). This implies that the real number \(r\) must lie strictly between \(-1\) and \(1\), and \(r\) cannot be \(0\). So, \(-1 < r < 1\) and \(r \neq 0\).
We need to determine if \(r^n < 1\) is always true under this condition, where \(n\) is a natural number.
Since \(r^n < 1\) is true for all values of \(r\) satisfying Statement-I and for all natural numbers \(n\), Statement-I alone is sufficient to answer the question affirmatively.
Statement-II provides the inequality \(0 < r^3 < 2\). By taking the cube root, we find \(0 < r < \sqrt[3]{2}\). Since \(\sqrt[3]{2}\) is approximately \(1.26\), this means \(r\) is a positive number less than approximately \(1.26\).
This condition alone does not guarantee that \(r^n < 1\). Consider \(r = 1.1\). This value satisfies \(0 < r < \sqrt[3]{2}\) because \(1.1^3 = 1.331\), which falls within the range \((0, 2)\).
However, if \(n=1\), then \(r^n = 1.1^1 = 1.1\). Since \(1.1\) is not less than \(1\), the condition \(r^n < 1\) is not met.
Therefore, Statement-II alone is not sufficient to answer the question.
To determine if both statements together are sufficient, we combine their conditions:
If \(0 < r < 1\), then for any natural number \(n\), \(r^n\) will always be positive and less than \(1\). For example, \((0.5)^n\) is always less than \(1\) for \(n \ge 1\).
Thus, using both statements together, we can definitively answer that \(r^n < 1\).
Statement-I alone is sufficient to answer the question (\(r^n < 1\)). Statement-II alone is not sufficient. Therefore, the question can be answered using one of the statements alone, but not using the other statement alone. This corresponds to Option A.
What is the sum of the largest and the smallest 4-digit numbers made by using single digit prime numbers (without repetition)?
What is the remainder when
\((17^{25} +19^{25})\)
is divided by 18?
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I. \(x\) is always divisible by 48.
II. \(x^2\) is always divisible by 144.
Select the answer using the code given below.
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