The first part of the journey covers a distance ($d_1$) of 30 km at a speed ($s_1$) of 6 km/hr.
The time taken ($t_1$) is calculated using the formula: Time = Distance / Speed.
$t_1 = \frac{d_1}{s_1} = \frac{30 \text{ km}}{6 \text{ km/hr}} = 5 \text{ hr}$
The second part of the journey has a distance ($d_2$) of 40 km and the time taken ($t_2$) is given as 5 hr.
Total distance ($D$) is the sum of distances of both parts:
$D = d_1 + d_2 = 30 \text{ km} + 40 \text{ km} = 70 \text{ km}$
Total time ($T$) is the sum of times taken for both parts:
$T = t_1 + t_2 = 5 \text{ hr} + 5 \text{ hr} = 10 \text{ hr}$
Average speed ($S_{avg}$) is calculated by dividing the total distance by the total time:
$S_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{D}{T}$
$S_{avg} = \frac{70 \text{ km}}{10 \text{ hr}} = 7 \text{ km/hr}$
The average speed for the whole journey is 7 km/hr.
A car runs first 275 km at an average speed of 50 km/h and the next 315 km at an average speed of 70 km/h. What is the average speed ( in km/h) for the entire journey?
Akhil rides first 12 km at a speed of 16 km/h and further 6 km at a speed of 20 km/h. Find his average speed (in km/h).
Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.
X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:
If a man travels at \(\frac{1}{x}\) km/h on a journey and returns at \(\rm \frac{1}{x^2}\) km/h, then his average speed for the journey is: